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  • 工作学习 / 学科技术 / Integer to String 的转换 -sxffff(lookingforjob); 2016-1-8 {234} (#9865962@0)
    有一个整数, 是从数据库的Sequence来的想把它转换成String, 格式要求是:Z0Z0Z0, 就是第1,3,5 位是字母,2,4,6位是0-9的数字, 应该怎样实现? 有API或代码吗? Java最好.

    1。 0 对应 A0A0A0
    2。 1 对应 A0A0A1
    3。 10 对应 A0A0B0
    4。 11 对应 A0A0B1
    • java code -mustang(mustang); 2016-2-8 {58} (#9934694@0) +1
      if I did not understand you wrong, here you are the code:
      • 非常感谢。 -sxffff(lookingforjob); 2016-2-10 {159} (#9938562@0)
        但好像有bug。
        i=295 A0A2J5
        i=296 A0A2J6
        i=297 A0A2J7
        i=298 A0A2J8
        i=299 A0A2J9
        i=300 A0A3A0
        i=301 A0A3A1
        i=302 A0A3A2
        i=303 A0A3A3

        300 应该是A0A2K0
        • Are you sure? My code gets Decimal 300: A0A1E0. because 300 = (1 * 26 + 4) * 10 + 0 -benbenli(大岭); 2016-2-11 (#9938988@0) +1
          • 写了个验证，300=A0A1E0； -sxffff(lookingforjob); 2016-2-13 {1333} (#9942852@0) +1
            本文发表在 rolia.net 枫下论坛public class Z0ToString {

            public static void main(String[] args) {
            for (int i = 0; i < 10000000; i++) {
            String convertedValue = convertBaseTenToString(i);
            System.out.println("i=" + i + " " + convertedValue);
            if (i!= convertStringToBaseTen(convertedValue)) {
            throw new RuntimeException("not equal: i = " + i + " convertStringToBaseTen(a)="+ convertStringToBaseTen(convertedValue));
            }
            }
            }

            static String convertBaseTenToString(int number) {
            char[] digits = { 'A', '0', 'A', '0', 'A', '0' };
            for (int i =digits.length -1; i>=0;i-- ) {
            int divisor = (i%2 !=0) ? 10 : 26;
            int a = (int)digits[i];
            int b = (a+ number % divisor);
            digits[i] = (char)b ;
            number /= divisor;
            }
            return new String(digits);
            }

            static int convertStringToBaseTen(String number) {
            int returnNumber=0;
            int base =1 ;
            for (int i = number.length()-1; i>=0; i--) {
            if (i%2 ==0) {
            int value = (number.charAt(i) -((int)'A'));
            if (i!= number.length()-1 ) {
            base = base * 10;
            }
            returnNumber = value* base + returnNumber;
            } else {
            int value = (number.charAt(i) -(int)'0');
            if (i!= number.length()-1 ) {
            base = base * 26;
            }
            returnNumber = value* base + returnNumber;
            }
            }
            return returnNumber;
            }
            }更多精彩文章及讨论，请光临枫下论坛 rolia.net
        • it might come from the way to split integer into digits, i will take a peek ,,, -mustang(大叔); 2016-2-11 (#9939632@0)
    • 个位、百位和万位十进制，十位、千位和十万位26进制吗？或者全部十进制？允许超过6位数吗？ -benbenli(大岭); 2016-2-10 (#9938225@0)
      • 个位、百位和万位十进制，十位、千位和十万位26进制吗？对 允许超过6位数吗？输入可以， 输出不可以。 -sxffff(lookingforjob); 2016-2-11 (#9938564@0)
    • answer='';"939159".split("").forEach(function(element, index, array) { answer+=(String.fromCharCode(65-(index%2)*17 + +1*element)); } );answer -firetrain(火车头); 2016-2-10 (#9938500@0)
      • looks very interesting; is '0' returning 'A0A0A0', '1' returns 'A0A0A1' ? -mustang(大叔); 2016-2-10 (#9938529@0)
      • 看不懂， 能解析一下吗？ -sxffff(lookingforjob); 2016-2-11 (#9938566@0)
        • 1000001 的结果是什么？ -sxffff(lookingforjob); 2016-2-11 (#9938570@0)
    • My code in C# (replaced leading spaces with dots to maintenance indentation). I used only basic language elements and it's easy to convert into other languages like Java or C or C++. Output of the numbers mentioned above are appended as well. -benbenli(大岭); 2016-2-11 {1656} (#9938882@0)
      本文发表在 rolia.net 枫下论坛using System;

      namespace Z0z0z0
      {
      ....class Program
      ....{
      ........public static string Z0ToString(uint number)
      ........{
      ............char[] digits = { 'A', '0', 'A', '0', 'A', '0' };
      ............for (int i = digits.Length -1; i >= 0 && number > 0; --i)
      ............{
      ................uint divisor = (uint)(digits[i] == '0' ? 10 : 26);
      ................digits[i] = (char)(((uint)digits[i]) + number % divisor);
      ................number /= divisor;
      ............}

      ............string z0 = string.Join("", digits);

      ............return z0;
      ........}

      ........static void Main(string[] args)
      ........{
      ............Console.WriteLine("Decimal {0}: {1}", 0, Z0ToString(0));
      ............Console.WriteLine("Decimal {0}: {1}", 1, Z0ToString(1));
      ............Console.WriteLine("Decimal {0}: {1}", 10, Z0ToString(10));
      ............Console.WriteLine("Decimal {0}: {1}", 11, Z0ToString(11));
      ............Console.WriteLine("Decimal {0}: {1}", 123, Z0ToString(123));
      ............for (uint i = 295; i <= 303; ++i)
      ............{
      ................Console.WriteLine("Decimal {0}: {1}", i, Z0ToString(i));
      ............}
      ............Console.WriteLine("Decimal {0}: {1}", 939159, Z0ToString(939159));
      ............Console.WriteLine("Decimal {0}: {1}", 1000001, Z0ToString(1000001));
      ........}

      ....}
      }
      // Output:
      Decimal 0: A0A0A0
      Decimal 1: A0A0A1
      Decimal 10: A0A0B0
      Decimal 11: A0A0B1
      Decimal 123: A0A0M3
      Decimal 295: A0A1D5
      Decimal 296: A0A1D6
      Decimal 297: A0A1D7
      Decimal 298: A0A1D8
      Decimal 299: A0A1D9
      Decimal 300: A0A1E0
      Decimal 301: A0A1E1
      Decimal 302: A0A1E2
      Decimal 303: A0A1E3
      Decimal 939159: B3X2D9
      Decimal 1000001: B4U6E1更多精彩文章及讨论，请光临枫下论坛 rolia.net
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