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You should be able do it with minus and two subqueries. in oracle: select ... where rownum < 150 minus select ... where rownum < 100

sleepingchild (Sleeping Child)
(#144809@0)
2001-7-25 -04:00
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Back To Topic: query结果来自几个表的join, 如何拿到中间一部分记录, 如: 第100 条到第150条.

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