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You don't need because it already have: C::C():M_B(&M_A) { B b = M_B; } , this is absolutely definition. As to the BYTE, it depends on the compiler.
guest:Zack
(#155207@0)
Last Updated: 2001-8-3
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这是一家公司C++面试题,以下代码有什么错误?
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