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Sorry about late. I was answering a phone call.

contact (Contact)
This one seems working:

select T2.A, T1.B from T T1, T T2
where T1.A = T2.A group by T2.A, T1.B having count(T2.A)>1
(#260300@0)
2001-11-13 -04:00
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Back To Topic: 闲来无事, 出道ORACLE SQL的题考考大家. 这是在下几个月前工作中遇到的问题, 看似简单, 其实不然.

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